Answer:
The answer to your question is Volume = 11.47 L
Explanation:
Data
Pressure = 221 kPa
Temperature = 32°C
moles = 1
Volume = ?
R = 0.082 atm L / mol°K
Process
1.- Convert pressure to atm
Pressure = 221 kPa = 221000 Pa
1 atm --------------------- 101325 Pa
x --------------------- 221000 Pa
x = (221000 x 1) / 101325
x = 2.18 atm
2.- Convert temperature to °K
°K = 32 + 273
= 305°
3.- Substitution
PV = nRT
- Solve for V
V = nRT / P
- Substitution
V = (1)(0.082)(305) / 2.18
- Result
V = 11.47 L
Answer:
The volume of the tire is 11.5 L
Explanation:
Step 1: Data given
Pressure of the car tire = 221 kPa = 2.1811 atm
Number of moles gas = 1.0 mol
Temperature = 32.0 °C
Step 2: Calculate the volume
p*V = n*R*T
⇒ with p = the pressure = 2.1811 atm
⇒ with V = the volume of the tire = TO BE DETERMINED
⇒ with n= The number of moles gas = 1 mol
⇒ with R = the gas constant = 0.08206 L*atm/mol*K
⇒ with T = the temperature = 305 K
V = (n*R*T) / p
V = (1.0 * 0.08206 * 305 ) / 2.1811 atm
V = 11.5 L
The volume of the tire is 11.5 L
