Answer:
The answer to your question is V = 33 L
Explanation:
Data
R = 0.082 atm L / mol°K
Volume = ?
moles = 1.24
Temperature = 35°C = 273 + 35 = 308°K
Pressure = 96.2 kPa
Process
1.- Convert kPa to atm
1000 Pa -------------------- 1 kPa
x -------------------- 96.2 kPa
x = (96.2 x 1000) / 1
x = 96200 Pa
1 atm ----------------------- 101325 Pa
x ---------------------- 96200 Pa
x = (96200 x 1) / 101325
x = 0.949 atm
2.- Substitute in the Ideal gas law
PV = nRT
- Solve for V
V = nRT / P
V = (1.24)(0.082)( 308) / 0.949
3.- Result
V = 31.32 / 0.949
V = 33 L
Answer:
33.0 L is occupied
Explanation:
Step 1: Data given
Number of moles of the gas = 1.24 moles
Temperature = 35.0 °C = 308 K
Pressure = 96.2 kPa = 0.9494202 atm
Step 2: Calculate volume
p*V = n*R*T
⇒ with p= The pressure = 0.9494202 atm
⇒ with V= The volume of the gas = TO BE DETERMINED
⇒with n = The moles of gas = 1.24 moles
⇒with R = the gas constant = 0.08206 L*atm/K*mol
⇒with T = the temperature = 308 K
V = (n*R*T) / p
V = (1.24 * 0.08206 * 308) / 0.9494202
V = 33.0 L
33.0 L is occupied
