Respuesta :
Explanation:
work = force ×distance
1 w = ? f= 200 d= 1.3
w = f ×d
=200×1.3
= 269 joule
2 w=? f=40. d=6
w= 40/6
= 240 joule
3. w=? m=254. f= ? d=3
w=f=mg. f= 254×10. f= 2540
w=f×d
=2540×3
= 7620 joule
Answer:
Explanation:
1) to calculate the workdone in lifting a 200N cough a distance of 1.3m from a loading lamp
our workdone = ?
Force = 200N
Distance = 1.3 m
from the formula of workdone
W = F × D
work done = 200 × 1.3
workdone = 260 joules
2) workdone = ?
Force = 40 N
Distance = 6m
workdone = force × distance
W = 40 × 6
Workdone = 240 joules
3) workdone = ?
mass = 254kg
distance = 3m
workdone = force × distance
force = mg
f= 254 × 9.8
F = 2489.2 N
workdone = force × distance
workdone = 2489.2 × 3
workdone = 7467.6 joules