Respuesta :

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Answer:

  • The volume of CO₂(g) produced at STP when 0.05 moles of C₂H₄(g) was burnt in O₂(g) is 2.24dm³

Explanation:

The question is incomplete.

This is the complete question:

Consider the reaction by the following equation:

           C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)

The volume of CO₂(g) produced at s.t.p when 0.05 moles of C₂H₄(g) was burnt in O₂(g) is ________

[Molar Volume of gas = 22.4dm³]

   A. 1.12dm³

   B. 2.24dm³

   C. 3.72dm³

   D. 4.48dm³

Solution

1. Write the mole ratio between CO₂(g) and C₂H₄(g)

  •  1 mol C₂H₄(g) : 2 mol CO₂(g)

2. Multiply the 0.05 moles of C₂H₄(g) by the mole ratio

  • 0.05 mol C₂H₄ × 2 mol CO₂ / 1 mol C₂H₄(g) = 0.10 mol CO₂

3. Convert moles of CO₂ to volume at STP using the molar volume at STP

  • 0.10 mol CO₂ × 22.4 dm³ / mol = 2.24 dm³

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