Solution:
The total capacitance when two capacitors are connected in series is:
[tex]C_{total} = \frac{C_1 \times C_2}{C_1 + C_2}[/tex]
From given,
A circuit contains a 20 pF capacitor and a 60 pF capacitor connected in series
[tex]C_1 = 20\ pF\\\\C_2 = 60\ pF[/tex]
Substituting the values we get,
[tex]C_{total } = \frac{ 20 \times 60}{20 + 60}\\\\C_{total } = \frac{ 1200}{80}\\\\C_{total } = 15[/tex]
Thus the total capacitance of circuit is 15 pF