The Shark's teeth has a base of 2 cm and height of 1 cm.
Step-by-step explanation:
Step 1 :
Given,
the area of the shark's triangular teeth = 1 sq cm
Let b be the base and h be the height of the shark's triangular teeth.
We have the teeth's height is 1 cm short than the base
So h = b - 1
Step 2 :
Area of Triangle = ([tex]\frac{1}{2}[/tex]) × b × h = 1
Substituting h = b -1
([tex]\frac{1}{2}[/tex]) × b × (b-1) = 1
=> b² - b = 2 = > b²-b-2 = 1
Solving for b we have
(b-2)(b+1) = 0
b = 2 or b = -1
Since b is the base , we take the positive value as length/distance cannot be negative.
So b = 2
h = b - 1 = 2 - 1 = 1
h = 1
Step 3 :
Answer :
The Shark's teeth has a base of 2 cm and height of 1 cm.
