Answer:
Therefore, we have 6, 9, 12, and 15, that are the first, second, third and fourth consecutive multiples of 3, such the product of 6, 12 and 15 is 1,080.
Step-by-step explanation:
Let's find the factors of 1,080, as follows:
1,080 Dividing by 2 (1,080/2)
540 Dividing by 2 (540/2)
270 Dividing by 2 (270/2)
135 Dividing by 3 (135/3)
45 Dividing by 3 (45/3)
15 Dividing by 3 (15/3)
5 Dividing by 5 (5/5)
1
In consequence, we have:
5 * 3 * 3 * 3 * 2 * 2 * 2
Let's find out what multiples of 3 there are:
5 * 3 = 15 is a multiple of 3,
And 3 * 3 * 2 * 2 * 2 is remaining.
3 * 2 = 6 is also a multiple of 3,
And 3 * 2 * 2 is remaining
3 * 2 * 2 = 12 is also a multiple of 3.
Therefore, we have 6, 9, 12, and 15, that are the first, second, third and fourth consecutive multiples of 3, such the product of 6, 12 and 15 is 1,080.
Given:
Please find the question.
To find:
Find four consecutive multiples of 3.
Solution:
Assuming the set of first number is "3x"
So,
[tex]\to 3x \times (3x+6) \times (3x+9)=1080\\\\[/tex]
[tex]\to x=2 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{X should be integer} \\\\[/tex]
Therefore, the four number is "[tex]6, 9, 12, 15[/tex]".
Learn more about the numbers:
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