6.6 g
Explanation:
The mole ration between CaCO₃and CO₂ is 1 : 1
Because the molar mass of CaCO₃ is 100.0869 g/mol the amount of moles used in this chemical reaction is;
15/ 100
This will be similar to the moles of CO₂
Because the molar mass of CO₂ is 44g, then well multiply by the moles;
15/100 * 44
= 6.6 g
