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Consider the reaction below.

Upper C upper C l subscript 5 (g) double-headed arrow upper P upper C l subscript 3 (g) plus upper C l subscript 2 (g).

At 500 K, the reaction is at equilibrium with the following concentrations.

[PCI5]= 0.0095 M
[PCI3] = 0.020
[CI2] = 0.020 M

What is the equilibrium constant for the given reaction?

Respuesta :

arsilan324

Answer:

Kc = 0.042

Explanation:

PCl₅ → PCl₃ + Cl₂

The equilibrium constant's equation will be

Kc = [PCl₃] [Cl₂] / [PCl₅]

Kc = (0.02 x 0.02) / 0.0095

Kc = 0.0421

The equilibrium constant for the given reaction is 0.0421.

q6t5

Answer:

(A

Explanation:

edg 2020

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