Answer:
x+3*1/x=52/7
7x^2/7x+21/7x=52x/7x
7x^2-52x+21=0
I solve this with the quadratic formula
Solution of ax^2+bx+c=0, a≠0 are :
x1= [tex]\frac{-b+\sqrt{b^2-4ac}}{2a}[/tex] and x2= [tex]\frac{-b-\sqrt{b^2-4ac}}{2a}[/tex]
so a=7, b=-52,c=21
x1=[tex]\frac{52+\sqrt{52^2-4*7*21} }{14}[/tex]= (52+46)/14=98/14=7
x2=(52-46)/14=6/14=3/7
Step-by-step explanation:
