Answer:
[tex]SA=88.8\ m^2[/tex]
Step-by-step explanation:
The picture of the question in the attached figure
Part 1) using a formula
we know that
The surface area of a triangular prism is equal to
[tex]SA=2B+PL[/tex]
where
B is the area of the triangular face
L is the length of the triangular prism
P is the perimeter of the triangular face
Find the area of the triangular face B
[tex]B=\frac{1}{2}(3)(2.6)= 3.9\ m^2[/tex]
Find the perimeter of the triangular face P
[tex]P=3+3+3=9\ m[/tex]
we have
[tex]L=9\ m[/tex]
substitute
[tex]SA=2(3.9)+9(9)=88.8\ m^2[/tex]
Part 2) Using the net
The surface area is equal to the area of two triangular faces plus the area of three rectangular faces
so
[tex]SA=2[\frac{1}{2}(3)(2.6)]+3[(9)(3)]=88.8\ m^2[/tex]
