Answer:
Part 1) [tex]y=-\frac{2x}{B}x+\frac{16}{B}[/tex]
Part 2) [tex]y=-\frac{1}{4}x+2[/tex]
Step-by-step explanation:
Part 1)
we know that
The equation of the line in slope intercept form is equal to
[tex]y=mx+b[/tex]
we have
[tex]2x+By=16[/tex]
Isolate the variable y
subtract 2x both sides
[tex]By=-2x+16[/tex]
Divide by B both sides
[tex]y=-\frac{2x}{B}x+\frac{16}{B}[/tex]
Part 2)
we know that
The equation of the line in slope intercept form is equal to
[tex]y=mx+b[/tex]
we have
[tex]2x+8y=16[/tex]
Isolate the variable y
subtract 2x both sides
[tex]8y=-2x+16[/tex]
Divide by 8 both sides
[tex]y=-\frac{2x}{8}x+\frac{16}{8}[/tex]
Simplify
[tex]y=-\frac{1}{4}x+2[/tex]
