Answer:
15.8 M CH3OH
Explanation:
Molarity is measured in Moles per liter of total solution.
Here, we are given 56% weight methanol and this means 44% solvent. We can use whatever ratio we would like but just calling it out of 100 g is the easiest. This means we have 56 g of methanol and 44 g of solvent. It says aqueous, so that means the solvent is water.
First, get the moles of the solute, methanol.
(56 g) * (1 mol / 32.042 g) = 1.75 mol methanol
Second, get the total volume using the given density and the grams we chose.
(100 g) / (0.9046 g / 1 mL) = 110.55 mL
Convert to liters
= 0.111 L
Third, use these values to find molarity.
1.75 mol / 0.111 L
= 15.8 M CH3OH