Answer:
for green, dominant:
- F1 generation: Gy × Gy ...(from punnet square)
phenotype: 4 green ; 0 yellow
∴ all are genotypically heterozygous, and green
- F1 generation: Gy× yy ...(from punnet square)
phenotype: 2 green; 2 yellow
∴ all are genotypically heterozygous, 2 are green and 2 yellow
for yellow, dominant:
- F1 generation: Yg × Yg ...(from punnet square)
phenotype: 4 yellow; 0 green
∴ all are genotypically heterozygous, and yellow
- F1 generation: Yg × gg ...(from punnet square)
phenotype: 2 yellow; 2 green
∴ all are genotypically heterozygous, 2 are green and 2 yellow
Explanation:
Punnett squares are a diagrammatic way of deciding the characteristics of hybrid offspring created by crosses in genetic breeding. Parental genotypes and phenotypes are widely recognized, and all usually obey normal Mendelian ratios and inheritance.
Mendelian genetics focuses on the origin or heritability of characteristics. Such traits are packed into one's own gamete, acquired by themselves, and sometimes display superiority, where one's impact can mask those of another trait.
These are called the Law of Segregation, Independent assortment and Dominance respectively.
For this cross...
Assuming Green= dominant
Parent generation or P generation:
gametes: G → pod color green dominant (G), yellow recessive (y)
Assuming heterozygousity
P generation: Gy× yy
green × yellow
F1 generation: Gy× yy ...(from punnet square)
phenotype: 2 green; 2 yellow
∴ all are genotypically heterozygous, 2 are green and 2 yellow
Assuming true breeding parents (homozygous)
P generation: GG × yy
green × yellow
F1 generation: Gy × Gy ...(from punnet square)
phenotype: 4 green ; 0 yellow
∴ all are genotypically heterozygous, and green
Assuming yellow= dominant
Parent generation or P generation:
gametes: Y → pod color y dominant (Y), green recessive (g)
Assuming true breeding parents(homozygous)
P generation: YY × gg
Yellow × green
F1 generation: Yg × Yg ...(from punnet square)
phenotype: 4 yellow; 0 green
∴ all are genotypically heterozygous, and green
Assuming heterozygousity
P generation: Yg× gg
yellow ; green
F1 generation: Yg × gg ...(from punnet square)
phenotype: 2 yellow; 2 green
∴ all are genotypically heterozygous, 2 are green and 2 yellow
Each punnet cross is attached in order below
