Specific heat of the material thus calculated is 0.22 J/ g °C
Explanation:
Given:
Mass of the sample (m) = 50g
Heat energy = Q = 660 J
Temperature get raised from 20° C to 80° C
To Find:
Specific Heat of the material.
Formula to be used:
Q = m×C×ΔT
where we know that,
Heat energy = Q = 660 J
Mass = m = 50 g
ΔT = 80 - 20 = 60° C
Now to calculate the specific heat of the material (c) we must substitute all the values, Then we get,
[tex]C=\frac{Q}{m \times \Delta T}[/tex]
[tex]=\frac{660 \mathrm{J}}{50 \mathrm{g} \times 60^{\circ} \mathrm{C}}[/tex]
[tex]=0.22 \frac{J}{g^{\circ} \mathrm{C}}[/tex]
Thus the Specific heat of the material is 0.22 J/ g °C.
