A line passes through point (-2, 5) and has a slope of . Points A(x, 3) and B(-2, y) lie on the line.
The value of x is
, and the value of y is
.

Respuesta :

The question is incomplete. The complete question is here.

A line passes through point (-2, 5) and has a slope of 2/3. Points A(x, 3) and B(-2, y) lie on the line.

The value of x is ___, the value of y is ___.

Answer:

The value of x is -5, and the value of y is 5

Step-by-step explanation:

The form of a linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept (value y at x = 0), to find b substitute x and y in the equation by the coordinates of a point on the line

∵ The slope of the line is [tex]\frac{2}{3}[/tex]

∴ m = [tex]\frac{2}{3}[/tex]

∵ The form of the equation is y = m x + b

∴ y =  [tex]\frac{2}{3}[/tex] x + b

- Substitute x and y by the coordinates of a point on the line

∵ The line passes through point (-2 , 5)

∴ x = -2 and y = 5

∵ 5 =  [tex]\frac{2}{3}[/tex] (-2) + b

∴ 5 =  [tex]\frac{-4}{3}[/tex] + b

- Add [tex]\frac{-4}{3}[/tex] to both sides

∴ [tex]\frac{19}{3}[/tex] = b

∴ y = [tex]\frac{2}{3}[/tex] x + [tex]\frac{19}{3}[/tex]

∵ Point A (x , 3) lies on the line

- Substitute y by 3 to find x

∴ 3 = [tex]\frac{2}{3}[/tex] x + [tex]\frac{19}{3}[/tex]

- Subtract [tex]\frac{19}{3}[/tex] from both sides

∴ [tex]\frac{-10}{3}[/tex] =  [tex]\frac{2}{3}[/tex] x

- Divide both sides by  [tex]\frac{2}{3}[/tex]

∴ -5 = x

The value of x = -5

∵ Point B (-2 , y) lies on the line

- Substitute x by -2 to find y

∴ y = [tex]\frac{2}{3}[/tex] (-2) + [tex]\frac{19}{3}[/tex]

∴ y =  [tex]\frac{-4}{3}[/tex] +  [tex]\frac{19}{3}[/tex]

∴ y =  [tex]\frac{15}{3}[/tex]

∴ y = 5

The value of y = 5