Uv = 8 and wx=5 find the missing measure of a rhombus

Answer:
Step-by-step explanation:
At first we should know the following about the rhombus
1) All sides are congruent
2) The diagonals are perpendicular and bisects each other.
Given UV = 8 and WX = 5
So, according to (1)
TU = UV = VW = WT = 8
And according to (2)
WX = UX = 5
And ΔWXV is a right triangle at ∠x
So, XV² = WV² - WX² = 8² - 5² = 64 - 25 = 39
∴XV = √39
So, XV = XT = √39
So, the missing measure of a rhombus are as following:
The missing measures of the rhombus are: [tex]TU = 8[/tex], [tex]WT=8[/tex], [tex]WV = 8[/tex], [tex]TX = 6.24[/tex] and [tex]XU = 5[/tex]
The given parameters are:
[tex]UV = 8[/tex]
[tex]WX = 5[/tex]
All sides of a rhombus are equal.
So, we have:
[tex]TU = 8[/tex]
[tex]WT=8[/tex]
[tex]WV = 8[/tex]
The diagonals of a rhombus are perpendicular; this means that the triangle WXV is right-angled.
So, we can make use of the following Pythagoras theorem
[tex]WV^2 = WX^2 + XV^2[/tex]
This gives
[tex]8^2 = 5^2 + XV^2[/tex]
[tex]64 = 25 + XV^2[/tex]
Subtract 25 from both sides
[tex]64 - 25 = XV^2[/tex]
[tex]39 = XV^2[/tex]
Rewrite as:
[tex]XV^2 = 39[/tex]
Take square roots
[tex]XV = 6.24[/tex]
This means that:
[tex]XV =TX = 6.24[/tex]
[tex]WX =XU = 5[/tex]
Hence, the missing side lengths are: [tex]TU = 8[/tex], [tex]WT=8[/tex], [tex]WV = 8[/tex], [tex]TX = 6.24[/tex] and [tex]XU = 5[/tex]
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