One mole of any gas at STP takes up 22.4 L
1 mole of gas = 22.4L
2.5 moles of gas takes up = ( 22.4 L/ 1 mole ) x 2.5 mole
= 56 L
Answer: m = 7.7 g Cl2
Explanation: To find mass of chlorine gas we will first derive the ideal gas law formula and find first the number of moles of Cl2. At STP, Pressure is equal to 1 atm and temperature is 273 K.
n= PV /RT
= 1 atm ( 2.5 L) /0.0821 L.atm / mole.K ( 273 K)
= 0.11 mole Cl2
Convert moles of Cl2 to grams using the molar mass of Cl2 which is 70 g Cl2.
0.11 mole Cl2 x 70 g Cl2 / 1 mole Cl2
= 7.7 g Cl2
