Answer:
-1.65
Explanation:
First of all, we find the position of the image by using the lens equation:
[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]
where:
f is the focal length of the lens
p is the distance of the object from the lens
q is the distance of the image from the lens
For the lens in this problem:
f = 21.0 cm (the focal length of a convex lens is positive)
p = 33.7 cm
Solving for q, we find the position of the image:
[tex]\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{21.0}-\frac{1}{33.7}=0.0179 cm^{-1}\\q=\frac{1}{0.0179}=55.7 cm[/tex]
Then, the magnification of the image is given by:
[tex]M=-\frac{q}{p}[/tex]
And substituting,
[tex]M=-\frac{55.7}{33.7}=-1.65[/tex]
Which means that the image is inverted (negative sign) and enlarged (because M is larger than 1).
