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Energy Conservation:
A bike rider approaches a hill at an initial velocity of 8.5 m/s. The mass of the bike and

rider is 85 kg. If the rider coasts up the hill, what is the final height the rider can reach?​

Respuesta :

opudodennis

Answer:

3.9 m

Explanation:

Assuming no energy losses then all kinetic energy is converted to potential energy

[tex]0.5mv^{2}=mgh[/tex] and making h the subject of the formula

[tex]h=\frac {v^{2}}{2g}[/tex] where m is the mass of bike rider and bike, v is the velocity,  and g is acceleration due to gravity. Taking g as 9.81 m/s2, v as 8.5 m/s then

[tex]h=\frac {8.5^{2}}{2\times 9.81}=3.946992864\approx 3.9 m[/tex]

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