Respuesta :
Answer:
7.328m/s
Explanation:
Given parameters:
height of table = 0.68m
final velocity of the ball = 6m/s
Unknown:
Initial velocity of ball = ?
Solution:
To solve this problem, we are going to employ the appropriate motion equation.
We must understand that this fall occurs in the presence of gravity;
V = U + 2gH
Where;
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height of the pool table
Since U is the unknown, let us make it the subject of the expression;
U = V - 2gH
U = 6 - (2 x 9.8 x 0.68) = 7.328m/s(deceleration)
The ball's initial velocity will be "7.328 m/s (deceleration)".
According to the question,
Height,
- h = 0.68 m
Final velocity,
- v = 6 m/s
We know the relation,
→ [tex]v = u +2 gh[/tex]
or,
→ [tex]u = v-2gh[/tex]
By putting the values, we get
[tex]= 6-(2\times 9.8\times 0.68)[/tex]
[tex]= 6 -13.328[/tex]
[tex]= 7.328 \ m/s[/tex] (deceleration)
Thus the approach above is right.
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