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A small college has 800 students, 10%, percent of which are left-handed. Suppose they take an SRS of 444 students. Let X= equals the number of left-handed students in the sample.
What is the probability that exactly 2 of the 4 students are left-handed?
You may round your answer to the nearest hundredth.

Respuesta :

reminder

Answer:

0.05

Step-by-step explanation:

fichoh

Using the binomial probability principle, the probability of choosing exactly 2 left handed persons ls 0.0486

For a binomial distribution :

  • P(x = x) = nCx * p^x * q^(n-x)
  • Probability, p = 0.10
  • q = 1 - p = 1 - 0.10 = 0.90
  • n = number of trials = 4

P(x = 2) = 4C2 × 0.10² × 0.90²

P(x = 2) = 6 × 0.01 × 0.81

P(x = 2) = 0.0486

Therefore, the probability that exactly 2 of the 4 are left handed ls 0.0486

Learn more :https://brainly.com/question/12474772

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