How much energy is required to raise the temperature of 3 kg of iron from 20° C to 25°C? Use the table below and this equation: Q=mc Delta T

The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)
Explanation:
Given:
Specific Heat capacity of Iron= 0.450 J/ g °C
To Find:
Required Energy to raise the Temperature
Formula:
Amount of energy required is given by the formula,
Q = mC (ΔT)
Solution:
M = mass of the iron in g
So 3 kg = 3000 g
C = specific heat of iron = 0.450 J/ g °C [ from the given table]
ΔT = change in temperature = 25° C - 20°C = 5°C
Plugin the values, we will get,
Q = 3000 g × 0.450 J/ g °C × 5°C
= 6,750 J
So the energy required is 6,750 J.