For this case we have a system of two equations with two variables:
[tex]y-6x = -4\\y-2x = 8[/tex]
Rewriting the system we have:
[tex]y = 6x-4\\y = 2x + 8[/tex]
Equaling the equations we have:
[tex]6x-4 = 2x + 8[/tex]
Subtracting 2x from both sides of the equation we have:
[tex]6x-2x-4 = 8\\4x-4 = 8[/tex]
Adding 4 to both sides of the equation we have:
[tex]4x = 8 + 4\\4x = 12[/tex]
Dividing by 4 on both sides of the equation we have:
[tex]x = \frac {12} {4}\\x = 3[/tex]
We find the value of the variable y:
[tex]y = 6x-4 = 6 (3) -4 = 18-4 = 14[/tex]
Thus, the system solution is:
[tex](x, y) :( 3,14)[/tex]
Answer:
[tex](x, y) :( 3,14)[/tex]
