Answer:
Read the explanation
Step-by-step explanation:
I am sure you missed out the base while typing the question.
If the complete question is
[tex] log_{3}(x + 5) = 2[/tex]
Then taking antilogarithm or rewriting in exponential form gives:
[tex]x + 5 = {3}^{2} [/tex]
Or
[tex] {3}^{2} = x + 5[/tex]
But if the complete question is:
[tex] log_{2}(x + 5) = 2[/tex]
Then the equivalent form is
[tex] {2}^{2} = x + 5[/tex]
