Answer:
The total work done on the baseball by the bat is 36.25 J.
Explanation:
The mass of the baseball is missing which is equal to 0.145 kg.
Given:
Mass of the baseball (m) = 0.145 kg
Initial speed of the baseball (v₁) = 20.0 m/s
Final speed of the baseball (v₂) = 30.0 m/s
Total work done on the baseball by the force exerted by the bat is given using the work-energy theorem which states that the total work done is equal to the change in the kinetic energy of the baseball.
Kinetic energy of a body of mass 'm' and speed 'v' is given as:
[tex]KE=\frac{1}{2}mv^2[/tex]
Therefore, the work done on the baseball is given as:
[tex]Work=\Delta KE\\\\Work=\frac{1}{2}m(v_2^2-v_1^2)\\\\Work=\frac{1}{2}\times (0.145\ kg)((30.0\ m/s)^2-(20.0\ m/s)^2)\\\\Work=(0.0725)(900-400)\ kg.m^2/s^2\\\\Work=0.0725\times 500=36.25\ J[/tex]
Therefore, the total work done on the baseball by the bat is 36.25 J.
