Answer:
The power developed by the turbine is 7553.8 kW
Explanation:
First we determine the mass flow rate of steam.
[tex]Mass \ flow \ rate \ (m) =\frac{volumetric\ flow \ rate }{density}[/tex]
given volumetric flow rate as 20 m³ /s
from steam table, density of steam at 0.8 bar = 2.087 kg/m³
[tex]Mass \ flow \ rate \ (m) =\frac{volumetric\ flow \ rate }{density} = \frac{20}{2.087} = 9.583 \ kg/s[/tex]
Based on energy equation and considering adiabatic flow;
[tex]W = -m[(h_2-h_1)+(\frac{V_2^2-V_1^2}{2})][/tex]
given;
V₁ = 200 m/s, V₂ = 150 m/s
from steam table, at saturated vapor pressure of 0.8 bar, h₂ = 2665.8 kJ/kg, also at vapor pressure of 40 bar and 500°C, h₁ = 3445.3 kJ/kg
[tex]W = -9.583[(2665.8-3445.3)+((\frac{150^2-200^2}{2})*\frac{1}{1000}) ] = 7553.8 \ kW[/tex]
Therefore, the power developed by the turbine is 7553.8 kW
