Answer:
[tex]0.185 ^{\circ}C[/tex]
Explanation:
When the water falls down, its initial gravitational potential energy is converted into internal energy. Therefore, we can write:
[tex]E_g=E_i\\mgh=mC\Delta T[/tex]
where
m is the mass of the water
g is the acceleration of gravity
h is the height of the water
C is the specific heat capacity of water
[tex]\Delta T[/tex] is the change in temperature
In this problem, we have:
h = 79 m is the change in height of the water
[tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity
[tex]C=4186 J/kg^{\circ}C[/tex] is the specific heat capacity of water
Re-arrnaging the equation, we can find the change in temperature:
[tex]\Delta T=\frac{gh}{C}=\frac{(9.8)(79)}{4186}=0.185 ^{\circ}C[/tex]
