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In a shuffleboard game, the puck slides a total of 12 m before coming to rest. If the coefficient ofkinetic friction between the puck and the horizontal board is 0.28, what was the initial speed of thepuck?

Respuesta :

Answer:

puck decelerates due to the kinetic frictional force μk mg

Explanation:

given data

total distance = 12 m

coefficient of kinetic friction = 0.28

solution

we will apply equation of motion that is

v² - u² = 2 × a × s    ................1

we know acceleration will be

a = [tex]\frac{-u^2}{2\times S}[/tex]  

Then we have

Force = mass × acceleration   .................2

m × [tex]\frac{-u^2}{2\times S}[/tex] = -μk mg

The puck decelerates due to the kinetic frictional force μk mg  

and frictional force is negative as it opposes the motion.

so we get initial velocity of the puck which is strike.

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