To develop this problem, we will apply the concepts related to Power, which is defined as the energy unit of a body per unit of time. Mathematically it can be written as,
[tex]P = \frac{E}{t}[/tex]
In this case the Energy is equivalent to the potential energy accumulated by the body therefore,
[tex]P = \frac{mgh}{t}[/tex]
Replacing with our data and taking the units to the International System we have to,
[tex]P = \frac{(300kg)(9.8m/s^2)(10)}{(2min)(\frac{60s}{1min})}[/tex]
[tex]P = 245W[/tex]
Therefore the average power rating required is 245W
