Respuesta :

Answer:

B

Step-by-step explanation:

Consider the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇒ [tex]\sqrt{ab}[/tex]

Given

4[tex]\sqrt{33x}[/tex] ← substitute x = 9

= 4[tex]\sqrt{33(9)}[/tex]

= 4( [tex]\sqrt{33}[/tex] × [tex]\sqrt{9}[/tex])

= 4([tex]\sqrt{33}[/tex] × 3)

= 12[tex]\sqrt{33}[/tex]

Thus the value of x is 9

Danboghiu66

Answer:

x=9 option B)

Step-by-step explanation:

12×V(33)=4×V(33x)=4×V(33)×V(x)

Where V(33) is short for sqrt(33).

After symplifying with V(33) we get:

12=4×V(x)

V(x)=3

x=9

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