The initial concentration of acetic acid will be "0.035 M".
Acetic acid
According to the question,
pH value = 3.10
Ka = 1.8 × 10⁻⁵
The chemical equation will be:
→ CH₃COOH [tex]\rightarrow[/tex] CH₃COO⁻ + H⁺
then,
HA [tex]\rightarrow[/tex] A⁻ + H⁺
We know that,
→ Ka = [tex]\frac{[A^-][H^+]}{[HA]}[/tex]
pH = -log[H⁺]
Now,
[H⁺] = [tex]10^{-3.1}[/tex]
= 7.0 × 10⁻⁴ M
[H⁺] = [A⁻]
hence,
The concentration will be:
→ [HA] = [tex]\frac{(7.94\times 10^{-4})^2}{1.8\times 10^{-5}}[/tex]
= 0.035 M
Thus the response above is correct.
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