Explanation:
Given that,
Mass of the baseball, m = 0.147 kg
The initial speed of the baseball, u = 42 m/s
The final speed of the baseball, v = -54 m/s (in opposite direction)
We need to find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat. The change in momentum is given by :
[tex]\Delta p=m(v-u)\\\\\Delta p=0.147\times (-54-(-42))\\\\\Delta p=-1.764\ kg-m/s[/tex]
We know that the impulse applied to it by the bat is equal to the change in momentum. So, the impulse is 1.764 kg-m/s.
