Respuesta :
The question is incomplete, here is the complete question:
Assume that concentrated aqueous NH₃ has a density of 0.252 g/mL (0.252 g of NH₃ per mL of liquid). Calculate the volume of NH₃ required to contain 0.442 mol?
Answer: The volume of ammonia required is 29.82 mL
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Molar mass of ammonia = 17 g/mol
Moles of ammonia = 0.442 moles
Putting values in above equation, we get:
[tex]0.442mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=(0.442mol\times 17g/mol)=7.514g[/tex]
To calculate the volume of ammonia, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of ammonia = 0.252 g/mL
Mass of ammonia = 7.514 g
Putting values in above equation, we get:
[tex]0.252g/mL=\frac{7.514g}{\text{Volume of ammonia}}\\\\\text{Volume of ammonia}=\frac{7.514g}{0.252g/mL}=29.82mL[/tex]
Hence, the volume of ammonia required is 29.82 mL
