Answer:
D(2,2)
Step-by-step explanation:
The diagonals of a parallelogram gram bisects each other.
Therefore E is the midpoint of AD.
Let the coordinates of D be (a,b).
By the midpoint rule:
[tex]( \frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}) = ( - 2, \frac{1}{2} )[/tex]
This implies that:
[tex]( \frac{ - 6+a}{2} ,\frac{ - 1+b}{2}) = ( - 2, \frac{1}{2} )[/tex]
This implies that:
[tex]( \frac{ - 6+a}{2} = - 2 ,\frac{ - 1+b}{2} = \frac{1}{2} ) [/tex]
[tex] ( - 6+a =- 4 , - 1+b = 1 ) \\ ( a =- 4 + 6 , b = 1 + 1 ) \\ ( a =2 , b =2 ) [/tex]
