Answer:
245N
Explanation:
pressure = [tex]\frac{FORCE}{AREA}[/tex]
Force = mg
g=9.8m/s²
Area = πd²/4
Assuming the pressure across the hydraulic system is constant, then;
[tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]
F₁ = Force on master cylinder
A₁ = Area of master cylinder
F₂ = Force on slave cylinder
A₂ = Area of slave cylinder
F₂ = mg
=10000 × 9.8
= 98000N
A₂ = πd² / 4
=π30²/4
=π900/4
=225π
A₁ = πd²/4
=π1.5²/4
=π2.25/4
=π0.562
recall, [tex]\frac{F_{1} }{A_{1} }[/tex] = [tex]\frac{F_{2} }{A_{2} }[/tex]
[tex]\frac{F_{1} }{0.5625\pi }[/tex] = [tex]\frac{98000}{225\pi }[/tex]
[tex]F_{1}[/tex] = 0.5625[tex]\pi[/tex] × 98000 / 225π
F₁ = 0.0025 × 98000
=245N
