Answer:
Step-by-step explanation:
Let x is the length of the square side.
We know: the two figures have the same area
<=> [tex]x^{2}[/tex] = π[tex]r^{2}[/tex] (r being radius)
<=> x = [tex]\sqrt{II}[/tex] r
perimeter square = 4x = 4*r*[tex]\sqrt{II}[/tex]
perimeter circle = 2*r*π
<=> 390 = 4*r*[tex]\sqrt{II}[/tex] + 2*r*π
<=> r = 29.16
=> perimeter square = 4*29.16*π
=> perimeter circle = 58.32π
