Among 500 freshmen pursuing a business degree at a university, 320 are enrolled in an economics course, 216 are enrolled in a mathematics course, and 129 are enrolled in both an economics and a mathematics course. What is the probability that a freshman selected at random from this group is enrolled in each of the following?

(a) an economics and/or a mathematics course

Respuesta :

Answer:

81.4% probability that a freshman selected at random from this group is enrolled in an economics and/or a mathematics course

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Total outcomes:

500 freshmen

Desired outcomes:

Enrolled in an economics and/or a mathematics course

Build the Venn's diagram.

I am going to say that:

A is the number of students enrolled in the economics course.

B is the number of students enrolled in the mathematics course.

We have that:

[tex]A = a + (A \cap B)[/tex]

In which a is the number of students who are enrolled in the economics course but not mathematics and [tex]A \cap B[/tex] is the number of students enrolled in both those courses.

By the same logic, we have that:

[tex]B = b + (A \cap B)[/tex]

129 are enrolled in both an economics and a mathematics course.

This means that [tex]A \cap B = 129[/tex].

216 are enrolled in a mathematics course

This means that [tex]B = 216[/tex]

[tex]B = b + (A \cap B)[/tex]

[tex]216 = b + 129[/tex]

[tex]b = 87[/tex]

320 are enrolled in an economics course

This means that [tex]A = 320[/tex]

[tex]A = a + (A \cap B)[/tex]

[tex]320 = a + 129[/tex]

[tex]a = 191[/tex]

We want

[tex]A \cup B = a + b + (A \cap B) = 191 + 87 + 129 = 407[/tex]

Probability:

[tex]P = \frac{407}{500} = 0.814[/tex]

81.4% probability that a freshman selected at random from this group is enrolled in an economics and/or a mathematics course