Answer:
Net ionic: [tex]Mg(OH)_{2}+2NH_{4}^{+}\rightarrow Mg^{2+}+2NH_{3}+2H_{2}O[/tex]
Explanation:
[tex]OH^{-}[/tex] in [tex]Mg(OH)_{2}[/tex] reacts with [tex]NH_{4}^{+}[/tex] to form [tex]NH_{3}[/tex] and [tex]H_{2}O[/tex].
Due to this acid-base reaction, [tex]Mg(OH)_{2}[/tex] become soluble whenever [tex]NH_{4}NO_{3}[/tex] is added to suspension of [tex]Mg(OH)_{2}[/tex].
In this reaction, [tex]NH_{4}NO_{3}[/tex] acts as an acid and [tex]Mg(OH)_{2}[/tex] acts as a base.
Molecular equation: [tex]Mg(OH)_{2}+2NH_{4}NO_{3}\rightarrow Mg(NO_{3})_{2}+2NH_{3}+2H_{2}O[/tex]
Total ionic: [tex]Mg(OH)_{2}+2NH_{4}^{+}+2NO_{3}^{-}\rightarrow Mg^{2+}+2NO_{3}^{-}+2NH_{3}+2H_{2}O[/tex]
Net ionic: [tex]Mg(OH)_{2}+2NH_{4}^{+}\rightarrow Mg^{2+}+2NH_{3}+2H_{2}O[/tex]