A projectile is shot upward from the surface of Earth with an initial velocity of 122 meters per second. Use the position function below for free-falling objects. What is its velocity after 2 seconds? After 12 seconds?

Respuesta :

Answer:

[tex]v(2) = 102.384\,\frac{m}{s}[/tex]

[tex]v(12) = 4.304\,\frac{m}{s}[/tex]

Step-by-step explanation:

The position function for the free-falling object is [tex]y(t) = 122\cdot t -4.904\cdot t^{2}[/tex], where t is measured in seconds and y is measured in meters. The velocity function is obtained by deriving it:

[tex]v(t) = 122-9.808\cdot t[/tex], where v is measured in meters per second.

Velocities at given times are, respectively:

[tex]v(2) = 102.384\,\frac{m}{s}[/tex]

[tex]v(12) = 4.304\,\frac{m}{s}[/tex]