Answer:
[tex]v_{esc} = 35434.918\,\frac{m}{s}[/tex]
Explanation:
The escape speed is given by following formula:
[tex]v_{esc} = \sqrt{\frac{2\cdot G\cdot M}{r} }[/tex]
Earth mass and radius are, respectively:
[tex]M_{earth} = 5.972\times 10^{24}\,kg[/tex]
[tex]R_{earth} = 6.371\times 10^6\,m[/tex]
Saturn mass and radius are, respectively:
[tex]M_{saturn} = 5.685\times 10^{26}\,kg[/tex]
[tex]R_{saturn} = 6.033\times 10^{7}\,m[/tex]
The required output is showed herein:
[tex]v_{esc} = \sqrt{\frac{2\cdot (6.67\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} )\cdot (5.685\times 10^{26}\,kg)}{6.033\times 10^{7}\,m} }[/tex]
[tex]v_{esc} = 35434.918\,\frac{m}{s}[/tex]
