Answer: The pH of the mixture at 0°C is 4.68
Explanation:
To calculate the pH at 0°C, we use the equation given by Henderson Hasselbalch:
[tex]pH=pK_a+\log(\frac{[salt]}{[acid]})[/tex]
[tex]pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})[/tex]
We are given:
[tex]pK_a[/tex] = negative logarithm of acid dissociation constant of acetic acid at 0°C = 4.78
[tex][CH_3COONa]=0.190M[/tex]
[tex][CH_3COOH]=0.239M[/tex]
pH = ?
Putting values in above equation, we get:
[tex]pH=4.78+\log(\frac{0.190}{0.239})\\\\pH=4.68[/tex]
Hence, the pH of the mixture at 0°C is 4.68