Respuesta :
Answer:
The coupled velocity of both the blocks is 1.92 m/s.
Explanation:
Given that,
Mass of block A, [tex]m_1=5\ kg[/tex]
Initial speed of block A, [tex]u_1=5\ m/s[/tex]
Mass of block B, [tex]m_2=8\ kg[/tex]
Initial speed of block B, [tex]u_2=0[/tex]
It is mentioned that if the two blocks couple together after collision. We need to find the common velocity immediately after collision. We know that due to coupling, it becomes the case of inelastic collision. Using the conservation of linear momentum. Let V is the coupled velocity of both the blocks. So,
[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{5\times 5+0}{(5+8)}\\\\V=1.92\ m/s[/tex]
So, the coupled velocity of both the blocks is 1.92 m/s. Hence, this is the required solution.
