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A small air compressor operates on a 2.8 hp (horsepower) electric motor for 9.1 hours a day. How much energy is consumed by the motor daily? 1 hp equals about 750 watts. Answer in units of J.

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asuwafoh

Answer:

68796000 J.

Explanation:

Energy: This  can be defined as the ability and the capacity to do work. The S.I unit of energy is Joules. (J).

From the question,

E = P×t............................. Equation 1

Where E = Energy, P = power, t = time.

Note: if the compressor operates 9.1 hours a day,

Given: P = 2.8 hp = (2.8×750) = 2100 J, t = 9.1 hours = 9.1×3600 = 32760

Substitute into equation 1

E = 2100×32760

E = 68796000 J.

onyebuchinnaji

The energy consumed by the electric motor is  6.88 x 10⁷ J.

The given parameters:

  • Electric power, P = 2.8 hp
  • Time, t = 9.1 hours
  • I hp = 750 W

The energy consumed by the electric motor is calculated as follows;

E = Pt

E = (2.8 x 750) x (9.1 x 3600)

E = 68796000 J

E = 6.88 x 10⁷ J

Thus, the energy consumed by the electric motor is  6.88 x 10⁷ J.

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