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A solution of sodium acetate (NaCH3COO) has a pH of 9.44. The acid-dissociation constant for acetic acid is 1.8×10−5. What is the molarity of the solution?

Respuesta :

mickymike92

Based on the dissociation constant and pH, the molarity of the sodium acetate (NaCH3COO) solution is 7.32 × 10^-15 M.

What is the molarity of a solution?

Molarity of a solution is the number of moles of the solute present in 1 L of solution.

The equation of the dissociation of the solution is given below:

  • NaCH3COO -----> CH3COO- + Na+
  • HA -----> A- + H+

Using the equation of dissociation constant, Ka:

  • Ka = [A-][H+]/[HA]

[H] = [A-]

[H+] = 10^-(pH)

[H+] = 10^-9.44

[H+] = 3.63 × 10^-10 M

Thus, [A-] = 3.63 × 10^-10 M

[HA] = [A-][H+]/Ka

[HA] = (3.63 × 10^-10 M)^2 / 1.8 × 10^-5

[HA] = 7.32 × 10^-15 M

Therefore, the molarity of the sodium acetate (NaCH3COO) solution is 7.32 × 10^-15 M.

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