Answer:
(a) Each piece is “berry or cherry” with probability p = 1/2. The proba-
bility of only berry or cherry pieces is p
12 = 1/4096.
Step-by-step explanation:
(b) Each piece is “not cherry” with probability 3/4. The probability all 12
pieces are “not pink” is (3/4)12 = 0.0317.
(c) For i = 1, 2, . . . , 6, let Ci denote the event that all 12 pieces are flavor i.
Since each piece is flavor i with probability 1/4, P[Ci
] = (1/4)12. Since
Ci and Cj are mutually exclusive,
P[F1] = P[C1 ∪ C2 ∪ · · · ∪ C4] = X
4
i=1
P[Ci
] = 4 P[C1] = (1/4)11
.