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A certain metal with atomic mass 2.9 × 10−25 kg has an interatomic bond with length 2.3 × 10−10 m and stiffness 48 N/m. What is the speed of sound in a rod made of this metal?

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anniwuanyanwu1

Answer:

Speed of sound = 2958.88m/s

Explanation:

The speed of sound is given by:

V = Sqrt(s/m)× d

Where a = stiffness of the metal

m = atomic mass of the metal

d,= distance

Given:

s= 48N/m

d= 2.3×10^-10m

m = 2.9×10^-25kg

V = Sqrt(48/(2.9×10^-25) × 2.3× 10^-10

V = Sqrt(1.655×10^26)×2.3×10^-10

V = 1.286×10^13 × 2.3×10^-10

V = 2958.88m/s

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