Answer:
4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ
Explanation:
2N2H4(2) + N204 (1) --> 3N2 (g) + 4H20 (g),AHO-1049 kJ
when 6 mol of nitrogen are formed?
The ratio of Nitrogen in the previous therrmochemical equation to when 6 mol f nitrogen are formed is 2; 6/3 = 2.
So to get the new thermoochemical equation, multiply all parameters in the given equation by 2.
We have;
4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ