Answer:
4.454 N.
Explanation:
The force on a current carrying conductor in a magnetic field is given as,
F = BILsinФ................... Equation 1
Where F = magnetic Force, B = magnetic Field, I = current, L = Length of the wire, Ф = The angle between the conductor and the Field.
Given: B = 0.289 T, I = 6.91 A, L = 6.7 m, Ф = 19°
Substitute into equation 1
F = 0.289(6.91)(6.7)sin19
F = 0.289×6.91×6.7×0.33
F = 4.454 N.
Hence the magnetic force = 4.454 N.
