Answer:
Pb = 1 atom
N = 2 atoms
O = 6 atoms
Na = 2 atoms
Cl = 2 atoms
Explanation:
Pb(NO3)2(aq) + 2NaCl(aq) → PbCl2(s) + 2NaNO3
To obtain the number of atoms of the different present, we simply do a head count of the individual elements. The following number of atoms of the different elements were obtained from the balanced equation:
Pb = 1 atom
N = 2 atoms
O = 6 atoms
Na = 2 atoms
Cl = 2 atoms